document.write( "Question 420248: Tell weather the parabola opens up or down and find the coordinates of the vertex and the axis of symmetry y=-x^2-4x+2 \n" ); document.write( "

Algebra.Com's Answer #293703 by lwsshak3(11628) $\"\"$ $\"About$

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Tell weather the parabola opens up or down and find the coordinates of the vertex and the axis of symmetry y=-x^2-4x+2\r
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\n" ); document.write( "\n" ); document.write( "y=-x^2-4x+2\r
\n" ); document.write( "\n" ); document.write( "Your questions can be answered after we change equation to standard form:
\n" ); document.write( "y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "completing the square to convert to standard form,
\n" ); document.write( "y=-(x^2+4x+4)+2+4
\n" ); document.write( "y=-(x+2)^2+6
\n" ); document.write( "This parabola opens downward because the coefficient of x^2 is negative. If the coefficient is positive, it will open upwards.
\n" ); document.write( "The coordinates of the vertex are (-2,6)
\n" ); document.write( "The axis of symmetry: x=-2
\n" ); document.write( "See what the graph looks like below:
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\n" ); document.write( "\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2-4x%2B2%29+\"$ \r
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