document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44459>Question 44459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> complex fractions\r<BR>\n" );
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document.write( "4 + 2 over x over x over 4+1 over 8\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29370 by </B><A HREF=/tutors/aboutme.mpl?userid=pvaka><B>pvaka(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pvaka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  = 2/x + 4(x)/1(x)  >> (4x + 2)/x  [FACTOR 4x + 2, you get 2(2x + 1)/x<BR>\n" );
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document.write( " = x (2)/4(2) + 1/8      (2x + 1)/8\r<BR>\n" );
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document.write( " = DIVIDE  2(2x + 1)/x   by  (2x + 1 )/8 <BR>\n" );
document.write( "  [MULTIPLY THE FIRST TERM WIH THE INVERSE OF THE SECOND TERM]<BR>\n" );
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document.write( " =  (2(2x + 1 )/x)(8/(2x +1)  **Both (2x + 1) cancelled each other out<BR>\n" );
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document.write( " =  (2)(8)/x\r<BR>\n" );
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document.write( " =   16/x<BR>\n" );
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document.write( "Hope this help! Good luck\r<BR>\n" );
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