document.write( "Question 420206: at noon a private plane left austin for los angeles, 2100 km away, flying ant 500 km/hr. One hour later a jet left Los angeles for austin at 700 km/hr. At what time did they pass each other? \n" ); document.write( "
Algebra.Com's Answer #293685 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Plane A speed 500 km/h \n" ); document.write( "Plane B speed 700 km/h \n" ); document.write( "Distance 2100 miles \n" ); document.write( "In 1 hour Plane A has traveled 500 miles before Plane B starts \n" ); document.write( "So distance = 1600 \n" ); document.write( "Let time they take to meet be x hours \n" ); document.write( "Time taken to meet is same \n" ); document.write( " \n" ); document.write( "t=d/r \n" ); document.write( "combined speed= 1200 mph \n" ); document.write( " \n" ); document.write( "1200 x = 1600 \n" ); document.write( "x= 1.33 hours \r \n" ); document.write( "\n" ); document.write( "They will meet at 2:33 pm \n" ); document.write( " \n" ); document.write( " |