document.write( "Question 420125: For how many integers n is n/(20-n) the square of an integer? \n" ); document.write( "
Algebra.Com's Answer #293682 by richard1234(7193)\"\" \"About 
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We could assign k to be an integer such that \"n%2F%2820-n%29+=+k%5E2\". Solve for n and you will get \"n+=+k%5E2%2820-n%29+=+20k%5E2+-+nk%5E2\" --> \"n%281%2Bk%5E2%29+=+20k%5E2\" --> \"n+=+20k%5E2%2F%281%2Bk%5E2%29+=+20+-+%2820%2F%281%2Bk%5E2%29%29\". Here, the positive factors of 20 are 1,2,5,10,20, so k^2 can equal 0,1,4,9, or 19. This implies that k = {0,1,2,3} and n = 0, 10, 16, or 18.\r
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\n" ); document.write( "\n" ); document.write( "Another way just as effective is to brute-force the problem. Most math teachers recommend against this, but I will sometimes brute-force a problem if I know for sure the method will work, if I know I'm counting all possible cases, and if the method does not take too much time. Here, we know that n can only be between 0 and 20; otherwise, \"n%2F%2820-n%29\" would be negative.
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