document.write( "Question 420154: from a point 50 feet in front ofrom a point 50 feet in front of a church, the angles of elevation to the base of the steeple and the top of the steeple are 35 degrees adn 47 degrees respectively. find the height of the steeple.f a church, the angles of elevation to the base of the steeple and the top of the steeple are 35 degrees and 47 degrees respectively. find the height of the steeple. \n" ); document.write( "
Algebra.Com's Answer #293676 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you know the angle and you know the length of the adjacent side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can find the length of the opposite side by using the tangent formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let A be the point 50 feet from the side of the church.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let B be the point at the base of the church.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let C be the point at the base of the steeple.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let D be the point at the top of the steeple.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the 35 degree angle forms the triangle ABC which takes you from the base of the church to the base of the steeple.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the 47 degree angle forms the triangle ABD which takes you from the base of the church to the top of the steeple.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 35 degrees equals BC / AB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 47 degrees equals BD / AB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AB = 50, so the equations become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 35 degrees equals BC / 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 47 degrees equals BD / 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of each equation by 50 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 35 degrees times 50 equals BC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 47 degrees times 50 equals BD.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use your calculator to find the tangenst to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".700207538 * 50 = BC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.07236871 * 50 = BD.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "35.01037691 = BC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "53.6184355 = BD\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the height of the steeple is equal to BD minus BC which equals 53.6184355 - 35.01037691 which equals 18.60805859 feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the height of the steeple is equal to 18.6 feet rounded to the nearest 10th of a foot.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a picture of the triangles created is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |