document.write( "Question 420164: 5n^2+19n+12
\n" ); document.write( "2v^2+11v+5
\n" ); document.write( "2n^2+5n+2
\n" ); document.write( "m^+2m-24
\n" ); document.write( "x^2-4x+24
\n" ); document.write( "k^2-13k+40
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Algebra.Com's Answer #293675 by dnanos(83)\"\" \"About 
You can put this solution on YOUR website!
\"%285n%5E2%2B19n%2B12%29\"= multiply 5*12=60...Search among the factors of 60 to find two of them having sum 19 ( that is...4*15=60 4+15=19)
\n" ); document.write( "after that we have:
\n" ); document.write( "\"%285n%5E2%2B15n%2B4n%2B12%29\"=
\n" ); document.write( "\"%285n%28n%2B3%29%2B4%28n%2B3%29%29\"=
\n" ); document.write( "\"%28%28n%2B3%29%285n%2B4%29%29\"
\n" ); document.write( "etc.....
\n" ); document.write( "Same way:
\n" ); document.write( "\"2v%5E2%2B11v%2B5+\"= We have 2*5=10 1*10=10 1+10=11
\n" ); document.write( "\"2v%5E2%2Bv%2B10v%2B5\"=
\n" ); document.write( "\"v%282v%2B1%29%2B5%282v%2B1%29\"=
\n" ); document.write( "\"%282v%2B1%29%28v%2B5%29\"\r
\n" ); document.write( "\n" ); document.write( "For a better way we use the \"sqrt%28b%5E2-4ac%29\" of the general formula \"ax%5E2%2Bbx%2Bc\" and if we find \"b%5E2-4ac%290\" then we cannot factorize.
\n" ); document.write( "I.e.the above:
\n" ); document.write( "\"x%5E2-4x%2B24\"
\n" ); document.write( "a=1,b=-4,c=24
\n" ); document.write( "and \"b%5E2-4%2A1%2A24=%28-4%29%5E2-4%2A24=-80%3C0\"\r
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