document.write( "Question 420127: i need help finding the axis of symmetry and vertex of the function f(x)=-2x^2, im confused because it doesnt give me B nor C only A. \n" ); document.write( "

Algebra.Com's Answer #293629 by Earlsdon(6294) $\"\"$ $\"About$

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When you compare the given equation: $\"f%28x%29+=+-2x%5E2\"$ with the general form for a quadratic equation: $\"f%28x%29+=+ax%5E2%2Bbx%2Bc\"$ , you can see that: a = -2, b = 0, and c = 0.
\n" ); document.write( "The x-coordinate of the vertex is given by:
\n" ); document.write( " $\"x+=+%28-b%29%2F2a\"$ and, since b= 0, the x-coordinate is x = 0.
\n" ); document.write( "Substitute x = 0 into the given equation: $\"y+=+-2x%5E2\"$ to get:
\n" ); document.write( " $\"y+=+-2%280%29%5E2\"$
\n" ); document.write( " $\"y+=+0\"$
\n" ); document.write( "The vertex is at (0, 0)
\n" ); document.write( "The graph of the given equation is a parabola that opens downward (negative coefficient of the $\"x%5E2\"$ term.
\n" ); document.write( "The equation of the axis of symmetry is $\"x+=+%28-b%29%2F2a\"$ or $\"x+=+0\"$ which is the y-axis.
\n" ); document.write( "Here's the graph of the given equation:
\n" ); document.write( " $\"graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C-2x%5E2%29\"$ \n" ); document.write( "

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