document.write( "Question 420127: i need help finding the axis of symmetry and vertex of the function f(x)=-2x^2, im confused because it doesnt give me B nor C only A. \n" ); document.write( "

Algebra.Com's Answer #293627 by dnanos(83) $\"\"$ $\"About$

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$\"y=-2x%5E2\"$
\n" ); document.write( " $\"graph%28300%2C100%2C-10%2C10%2C-10%2C10%2C-2x%5E2%29\"$ The symmetry axis is y'y and the vertex is the origin O(0,0).
\n" ); document.write( "This result can be proved also because of the formula of this function f(x)= $\"ax%5E2\"$ , where a=-2...
\n" ); document.write( "(i)This x squared gives f(x)=f(-x) ,that is for every x the symmetric points
\n" ); document.write( "(x,f(x)) and (-x,f(-x)) belong to the graph.[these points are (x,f(x),(-x,f(x))and we know the are y'y-symmetric as any two points (a,b) and (-a,b) are.]
\n" ); document.write( "(ii)a=-2 that is a<0
\n" ); document.write( "so $\"ax%5E2%3C=0\"$ ,that is the maximum value of f(x)=0 occurs when x=0,and (x,y)=(0,0) is the vertex of the parabola. \n" ); document.write( "

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