document.write( "Question 420119: Two small pitchers and one large pitcher can hold 8 cups of water. one large pitcher minus one small pitcher constitutes 2 cups of a water. How many cups of water can each pitcher hold? \n" ); document.write( "

Algebra.Com's Answer #293622 by Earlsdon(6294) $\"\"$ $\"About$

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Let the capacity of the large pitcher be L cups and the capacity of the small pitcher be S cups.
\n" ); document.write( "1) L+2S = 8 \"Two small pitchers (2S) and one large pitcher (L) can hold 8 cups of water.\"
\n" ); document.write( "2) L-S = 2 \"One large pitcher (L) minus one small pitcher (S) constitute 2 cups of water.\"
\n" ); document.write( "Solve equation 2) for L---> (L = S+2) and substitue into equation 1) to get:
\n" ); document.write( "1a) (S+2)+2S = 8 Solve for S.
\n" ); document.write( "1b) 3S+2 = 8 Subtract 2 from both sides.
\n" ); document.write( "1c) 3S = 6 Divide both sides by 3.
\n" ); document.write( "1d) S = 2 and
\n" ); document.write( "L = S+2
\n" ); document.write( "L = 2+2 = 4
\n" ); document.write( "The large pitcher can hold 4 cups.
\n" ); document.write( "The small pitcher can hold 2 cups. \n" ); document.write( "

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