document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420104>Question 420104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not understand the meaning of this problem and how to work it out, any help would be appreciated. Thanks, <BR>\n" );
document.write( "y varies jointly with x squared. If y = 1/4 when x=1, find the equation for y in terms of x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293606 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y varies jointly with x squared. <BR>\n" );
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document.write( "y = k*x^2<BR>\n" );
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document.write( "Solve for \"k\" using \" y = 1/4 when x=1\"<BR>\n" );
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document.write( "(1/4) = k*1^2<BR>\n" );
document.write( "k = (1/4)<BR>\n" );
document.write( "--------------------\r<BR>\n" );
document.write( "\n" );
document.write( "Find the equation for y in terms of x<BR>\n" );
document.write( "Equation: <BR>\n" );
document.write( "y = (1/4)x^2<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );