document.write( "Question 420085: In order to earn an A in a class, your test scores must average at least 92%. On the first 6 tests, you have an average of 91%. What score do you need to get on the last test to earn an A? Show your work.\r
\n" ); document.write( "\n" ); document.write( "Well I tried it myself And I think it's set out like this: 91+6=>92 I don't know If this is the right way to set it up. =/
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Algebra.Com's Answer #293590 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Having an average of 91 on 6 tests is the same as making exactly\r\n" );
document.write( "91 of all 6 tests.  So we will pretend that you made 91 on each\r\n" );
document.write( "of the first 6 tests:\r\n" );
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document.write( "1. On the 1st test you made 91\r\n" );
document.write( "2. On the 2nd test you made 91\r\n" );
document.write( "3. On the 3rd test you made 91\r\n" );
document.write( "4. On the 4th test you made 91\r\n" );
document.write( "5. On the 5th test you made 91\r\n" );
document.write( "6. On the 6th test you made 91\r\n" );
document.write( "7. On the 7th test you made x.\r\n" );
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document.write( "           91 + 91 + 91 + 91 + 91 + 91 + x         \r\n" );
document.write( "Average = --------------------------------- > 92\r\n" );
document.write( "                        7 \r\n" );
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document.write( "                                    546 + x\r\n" );
document.write( "                                   --------- > 92 \r\n" );
document.write( "                                       7\r\n" );
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document.write( "                                     546 + x > 644\r\n" );
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document.write( "                                           x > 98\r\n" );
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document.write( "You need to make at lease 98\r\n" );
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document.write( "Edwin
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