document.write( "Question 420061: How do you use the zero-factoring property when solving a quadratic equation? \n" ); document.write( "
Algebra.Com's Answer #293567 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "When a product \"AB+=+0\" then either \"A+=+0\" OR \"B+=+0\".\r
\n" ); document.write( "\n" ); document.write( "When you have a \"quadratic_+expression+=+0\", and \"can\"\"+factor\" it into two linear factors, then you have \"exactly\" that situation. \r
\n" ); document.write( "\n" ); document.write( "Then you simply need to solve two linear equations in place of the quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "So if you can factor a quadratic as \"%283x-5%29%282x%2B1%29=0\"..it has the same form as \"AB+=+0\" and so\r
\n" ); document.write( "\n" ); document.write( "either \"3x-5%29=0%29%29%29+...%7B%7B%7B3x+%965+=+0\" OR \"2x+%2B+1+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Solving each of these you get that either\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%2B+5%2F3\" OR \"x+=+-1%2F2\"\r
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