document.write( "Question 419968: How do I solve this problem... 5n^2-26n+21 \n" ); document.write( "
Algebra.Com's Answer #293546 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor this.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Looking at \"5n%5E2-26n%2B21\" we can see that the first term is \"5n%5E2\" and the last term is \"21\" where the coefficients are 5 and 21 respectively.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 5 and the last coefficient 21 to get 105. Now what two numbers multiply to 105 and add to the middle coefficient -26? Let's list all of the factors of 105:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factors of 105:\r
\n" ); document.write( "\n" ); document.write( "1,3,5,7,15,21,35,105\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1,-3,-5,-7,-15,-21,-35,-105 ...List the negative factors as well. This will allow us to find all possible combinations\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 105\r
\n" ); document.write( "\n" ); document.write( "1*105\r
\n" ); document.write( "\n" ); document.write( "3*35\r
\n" ); document.write( "\n" ); document.write( "5*21\r
\n" ); document.write( "\n" ); document.write( "7*15\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-105)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(-35)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(-21)\r
\n" ); document.write( "\n" ); document.write( "(-7)*(-15)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -26? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -26\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
First NumberSecond NumberSum
11051+105=106
3353+35=38
5215+21=26
7157+15=22
-1-105-1+(-105)=-106
-3-35-3+(-35)=-38
-5-21-5+(-21)=-26
-7-15-7+(-15)=-22
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From this list we can see that -5 and -21 add up to -26 and multiply to 105\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"5n%5E2-26n%2B21\", replace \"-26n\" with \"-5n%2B-21n\" (notice \"-5n%2B-21n\" adds up to \"-26n\". So it is equivalent to \"-26n\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5n%5E2%2Bhighlight%28-5n%2B-21n%29%2B21\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's factor \"5n%5E2-5n-21n%2B21\" by grouping:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285n%5E2-5n%29%2B%28-21n%2B21%29\" Group like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5n%28n-1%29-21%28n-1%29\" Factor out the GCF of \"5n\" out of the first group. Factor out the GCF of \"-21\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285n-21%29%28n-1%29\" Since we have a common term of \"n-1\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"5n%5E2-5n-21n%2B21\" factors to \"%285n-21%29%28n-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this also means that \"5n%5E2-26n%2B21\" factors to \"%285n-21%29%28n-1%29\" (since \"5n%5E2-26n%2B21\" is equivalent to \"5n%5E2-5n-21n%2B21\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"5n%5E2-26n%2B21\" factors to \"%285n-21%29%28n-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Jim
\n" ); document.write( "
\n" );