document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419914>Question 419914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help! How would I go about solving y = 5 sin 2(pi)(x) - 2? So that I can graph it? I don't thing I'm doing it right...<BR>\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293525 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How would I go about solving y = 5 sin 2(pi)(x) - 2? So that I can graph it?<BR>\n" );
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document.write( "You know that a sin curve is normally centered on the origin.<BR>\n" );
document.write( "Well move it down so its centered at -2.<BR>\n" );
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document.write( "You know how the period is normally 2pi.<BR>\n" );
document.write( "Find the period for your curve:<BR>\n" );
document.write( "Period = (2pi)/b<BR>\n" );
document.write( "Your b is (2pi)<BR>\n" );
document.write( "So your period is (2pi)/(2pi) = 1 radian<BR>\n" );
document.write( "----<BR>\n" );
document.write( "So one cycle of your sin curve starts at x = 0<BR>\n" );
document.write( "and ends at x = 1. It then repeats itself to<BR>\n" );
document.write( "the right and to the left.<BR>\n" );
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document.write( "The amplitude is 5 so the curve is centered<BR>\n" );
document.write( "at y= -2 and ranges from y = -7 up to y = 3<BR>\n" );
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document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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