document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419818>Question 419818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Choose the answer that best represents the foci of an ellipse with the equation 25x^2+38y^2=900.\r<BR>\n" );
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document.write( "(a) (-6, 0)<BR>\n" );
document.write( "(b) (+or- sqrt [11], 0)<BR>\n" );
document.write( "(c) (0, sqrt [11])<BR>\n" );
document.write( "(d) (+or- sqrt [6], 0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293492 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of the ellipse is:\r<BR>\n" );
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document.write( "   (25*x^2)/900)+(38*y^2)/900)=1\r<BR>\n" );
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document.write( "   X^2/36+y^2/(450/19)=1<BR>\n" );
document.write( "From the last equation we have: a=6 and b=sqrt(450/19)\r<BR>\n" );
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document.write( "c^2=36-(450/19)<BR>\n" );
document.write( "c^2=36-23.6\r<BR>\n" );
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document.write( "c^2=12.3<BR>\n" );
document.write( "c=3.5<BR>\n" );
document.write( " The focee of the ellipse are:(-3.5,0)  (3.5,0) </SPAN>\n" );
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