document.write( "Question 44440This question is from textbook Begining Algebra
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document.write( ": The difference of two numbers is 27. The second is 1 less than 3 times the first. What are the two numbers? \n" );
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Algebra.Com's Answer #29349 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! You can write the necessary equations right from the problem: \n" ); document.write( "Let the two numbers be x (the first number) and y (the second number).\r \n" ); document.write( "\n" ); document.write( "x - y = 27 The difference of two numbers is 27.\r \n" ); document.write( "\n" ); document.write( "y = 3x-1 The second is 1 less than three times the first. Substitute this into the first equation and solve for x.\r \n" ); document.write( "\n" ); document.write( "x - (3x-1) = 27 \n" ); document.write( "x - 3x + 1 = 27 Collect like-terms. \n" ); document.write( "-2x + 1 = 27 Subtract 1 form both sides. \n" ); document.write( "-2x = 26 Divide both sides by -2. \n" ); document.write( "x = -13\r \n" ); document.write( "\n" ); document.write( "y = 3x-1 \n" ); document.write( "y = 3(-13)-1 \n" ); document.write( "y = -39-1 \n" ); document.write( "y = -40\r \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "x-y \n" ); document.write( "-13-(-40) = -13 + 40 = 27\r \n" ); document.write( "\n" ); document.write( "y = 3x-1 \n" ); document.write( "-40 = 3(-13)-1 \n" ); document.write( "-40 = -39-1 \n" ); document.write( "-40 = -40\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |