document.write( "Question 419780: $2.77 in a coin jar- all pennies(x), nickels(y), and dimes(z). If there are 53 coins in all, and 4 more nickels than dimes, how many of each coin do you have. Setup all 3 equations in x,y,z and solve the equations to find x(pennies), y(nickels), and z(dimes). Note: 1 equation has only y and z. \n" ); document.write( "
Algebra.Com's Answer #293468 by stanbon(75887)\"\" \"About 
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$2.77 in a coin jar- all pennies(x), nickels(y), and dimes(z). If there are 53 coins in all, and 4 more nickels than dimes, how many of each coin do you have. Setup all 3 equations in x,y,z and solve the equations to find x(pennies), y(nickels), and z(dimes). Note: 1 equation has only y and z.
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\n" ); document.write( "Equations:
\n" ); document.write( "10d + 5n + p = 277 cents
\n" ); document.write( "d + n + p = 53
\n" ); document.write( "n = d+4
\n" ); document.write( "----
\n" ); document.write( "Rearrange:
\n" ); document.write( "d + n + p = 53
\n" ); document.write( "d - n + 0 = -4
\n" ); document.write( "10d+ 5n + p = 277
\n" ); document.write( "--------
\n" ); document.write( "Solve by any method you know to get:
\n" ); document.write( "d = 16 (# of dimes
\n" ); document.write( "n = 20 (# of nickels
\n" ); document.write( "p = 17 (# of pennies
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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