document.write( "Question 419780: $2.77 in a coin jar- all pennies(x), nickels(y), and dimes(z). If there are 53 coins in all, and 4 more nickels than dimes, how many of each coin do you have. Setup all 3 equations in x,y,z and solve the equations to find x(pennies), y(nickels), and z(dimes). Note: 1 equation has only y and z. \n" ); document.write( "
Algebra.Com's Answer #293468 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! $2.77 in a coin jar- all pennies(x), nickels(y), and dimes(z). If there are 53 coins in all, and 4 more nickels than dimes, how many of each coin do you have. Setup all 3 equations in x,y,z and solve the equations to find x(pennies), y(nickels), and z(dimes). Note: 1 equation has only y and z. \n" ); document.write( "------ \n" ); document.write( "Equations: \n" ); document.write( "10d + 5n + p = 277 cents \n" ); document.write( "d + n + p = 53 \n" ); document.write( "n = d+4 \n" ); document.write( "---- \n" ); document.write( "Rearrange: \n" ); document.write( "d + n + p = 53 \n" ); document.write( "d - n + 0 = -4 \n" ); document.write( "10d+ 5n + p = 277 \n" ); document.write( "-------- \n" ); document.write( "Solve by any method you know to get: \n" ); document.write( "d = 16 (# of dimes \n" ); document.write( "n = 20 (# of nickels \n" ); document.write( "p = 17 (# of pennies \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========= \n" ); document.write( " |