document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419707>Question 419707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 10-quart radiator contains a 30% concentration of antifreeze. how much of the sloution must be drained and replaced by 100% antifreeze to bring the solution up to 50% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293448 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100	----------------	x<BR>\n" );
document.write( "30	----------------	10-x<BR>\n" );
document.write( "50.00%	----------------	10		<BR>\n" );
document.write( "...<BR>\n" );
document.write( "100x	+30(10	-x)	=	50	*	10<BR>\n" );
document.write( "100x	+300-30	x=	500		<BR>\n" );
document.write( "100x-30	x=500-	300		<BR>\n" );
document.write( "70	x	-		=	200							<BR>\n" );
document.write( "/70											<BR>\n" );
document.write( "x=2.86	liters of 100.00%	\r<BR>\n" );
document.write( "\n" );
document.write( "2.86 liters of 30 % will have to be drained off.<BR>\n" );
document.write( "	<BR>\n" );
document.write( " </SPAN>\n" );
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