document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419664>Question 419664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> dear tutor i tried several times to solve this problem, but it was too hard for me. Tutor can you please solve this problem for me : A car left a garage on the highway at 100 km/h. Fifteen minutes later, a police cruiser left the same garage at 120 km/h in pursuit of the car. How long did it take the cruiser to catch up with the car? ( remember time must be in hours ) thank - you so much , greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293433 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car speed	100	mph					<BR>\n" );
document.write( "Police car speed	120	mph					<BR>\n" );
document.write( "Difference in time=			15 minutes = 1/4 hour<BR>\n" );
document.write( "Car will have covered		25	miles	befor police car starts<BR>\n" );
document.write( "catch up distance=		25	miles				<BR>\n" );
document.write( "catch up speed =		120	-100	mph			<BR>\n" );
document.write( "catch up speed =		20	mph				<BR>\n" );
document.write( "							<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed							<BR>\n" );
document.write( "catch up time=		25	/	20			<BR>\n" );
document.write( "catch up time=		1.25	hours				<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );