document.write( "Question 419667: hi tutor, i am so glad i found this website. I am in desperate need of help in math. I am a really hard worker, and am in grade nine. I need to finish a booklet too raise my mark, so i can get into the pure classes in highschool. I just cant seem to solve this problem. Can you please help me out, thanks. Question : A jet liner and a propeller driven aircraft leave two cities 3000 km apart at the same time and fly toward each other on a collision course. The flights are non-stop. If the propeller driven plane flies at 200 k /h and the jet at 600 km/h, how far will the get fly before these planes crash? ( we must provide a graph, equation, and show how we got it ) . Thank - you so much, this is greatly appreciated. (: \n" ); document.write( "
Algebra.Com's Answer #293422 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
We can say that if the propeller driven plane flies x kilometers at 200 km/h, then the jet will fly 3x kilometers, because the jet is going three times as fast (use Distance = rate*time to verify this). Their total distance apart is 3000 km, so\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3x + x = 3000 km\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4x = 3000 km\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 750 km\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We wish to find 3x, because this is the length the jet traveled. Hence, 3x = 3(750 km) = 2250 km.\r
\n" ); document.write( "\n" ); document.write( "A graph doesn't suit this problem very well as it is merely a simple algebraic equation, but I'll graph the propeller plane's distance over time versus the jet's:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"graph%28200%2C+200%2C+0%2C+5%2C+0%2C+3000%2C+200x%2C+600x%29\" (note that the y-axis increments far more than the x-axis. The jet's motion is shown in green)
\n" ); document.write( "
\n" );