document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419592>Question 419592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One train leaves a station heading due west. Two hours later a second train leaves the same station heading due east. The second train is traveling 15 mi/h faster than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate at which each train is traveling. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293421 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A speed	=	x	mph								<BR>\n" );
document.write( "Train B speed	=	x	+	15	mph						<BR>\n" );
document.write( "Train A has left 		2	hours early								<BR>\n" );
document.write( "Train A has traveled 		2	x	miles before Train B starts							<BR>\n" );
document.write( "The trains are travelling in opposite directions											<BR>\n" );
document.write( "so their combined speed =		2	x+	15	mph						<BR>\n" );
document.write( "Train B has traveled 		6	hours								<BR>\n" );
document.write( "Diatance  	580										<BR>\n" );
document.write( "2x+6(	2	x	+	15	)	=	580<BR>\n" );
document.write( "2x	+	12x	+	90	=	580			<BR>\n" );
document.write( "14	x	=	580	-90							<BR>\n" );
document.write( "14	x	=	490								<BR>\n" );
document.write( "	x	=	35	mph		Train A speed					<BR>\n" );
document.write( "			50	mph		Train B speed					<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );