document.write( "Question 419651: How would i find the age to the following problem?: This year i'm 3 times as old as my little sister. However six years ago I was 5 times as old as she was. How would I find the age of this person? \n" ); document.write( "
Algebra.Com's Answer #293412 by josmiceli(19441)\"\" \"About 
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Let \"a\" = my age now
\n" ); document.write( "Let \"b\" = my sister's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+a+=+3b+\"
\n" ); document.write( "(2) \"+a+-+6+=+5%2A%28b+-+6%29+\"
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (1) in (2)
\n" ); document.write( "(2) \"+3b+-+6+=+5%2A%28b+-+6%29+\"
\n" ); document.write( "(2) \"3b+-+6+=+5b+-+30+\"
\n" ); document.write( "(2) \"+2b+=+24+\"
\n" ); document.write( "\"+b+=+12\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"a+=+3b+\"
\n" ); document.write( "\"a+=+36\"
\n" ); document.write( "I'm 36 and my little sister is 12
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+3%2A12+-+6+=+5%2A%2812+-+6%29+\"
\n" ); document.write( "\"+36+-+6+=+5%2A6+\"
\n" ); document.write( "\"30+=+30+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );