document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419629>Question 419629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I need some help with finding the surface area of the solid right circular cylinder with r = 6cm and h = 4cm.\r<BR>\n" );
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document.write( "Can you please help :o) Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293403 by </B><A HREF=/tutors/aboutme.mpl?userid=dnanos><B>dnanos(83)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dnanos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dnanos><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Surface=curved area +2 times the base<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S=2pi%2Ar%2Ah%2B2pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"S=2pi%2Ar%2Ah%2B2pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S=2pi%2Ar%28h%2Br%29 ALIGN=MIDDLE  ALT=\"S=2pi%2Ar%28h%2Br%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A3.14%2A6%284%2B6%29 ALIGN=MIDDLE  ALT=\"2%2A3.14%2A6%284%2B6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6.28%2A6%2A10 ALIGN=MIDDLE  ALT=\"6.28%2A6%2A10\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<BR>\n" );
document.write( "376.8 </SPAN>\n" );
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