document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5703>Question 5703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for r: 4(r-2)= 2(r+8)\r<BR>\n" );
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document.write( "This is how I am trying to do it:<BR>\n" );
document.write( "I isolated the variable r <BR>\n" );
document.write( "I multiplied the the terms<BR>\n" );
document.write( "left side first, then right side and got:<BR>\n" );
document.write( "4r-8 = 2r+16<BR>\n" );
document.write( "Then I isolate r by subtracting both sides by 2 and got:<BR>\n" );
document.write( "2r-8 = r+16<BR>\n" );
document.write( "Then I isolated r by adding both sides by 2<BR>\n" );
document.write( "4r-8 = r+16<BR>\n" );
document.write( "Then I isolate r by dividing both sides by 2<BR>\n" );
document.write( "2r-8 = 1r+16\r<BR>\n" );
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document.write( "Ultimately I got 4 <BR>\n" );
document.write( "and I seemed to got lost in the equation, please help :(<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2934 by </B><A HREF=/tutors/aboutme.mpl?userid=prince_abubu><B>prince_abubu(198)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prince_abubu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You did good on distributing across the parentheses to get 4r - 8 = 2r + 16.\r<BR>\n" );
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document.write( "You tried to subtract 2 from both sides off the 4r and the 2r. However, this doesn't lower the 4r to 2r, or the 2r to r.\r<BR>\n" );
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document.write( "In Algebra, you can only add or subtract like terms. For now, a term is a single number by itself, a single variable by itself, or a combination of a single number (constant) and a letter (variable) multiplied together. \"Like terms\" means that the terms MUST be either all constants, or contain the same variable before you may combine them by addition or subtraction.\r<BR>\n" );
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document.write( "The attempt to say that 4r - 2 to equal 2r seems somewhat of a valid guess. However, since 4r and 2 don't have like terms (because one has a variable and the other doesn't), you can't combine the two by addition or subtraction.\r<BR>\n" );
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document.write( "In your case, your best bet would be to subtract 2r from both sides. Now you can say 4r - 2r = 2r because 4r and 2r are like terms.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4r+-+8+=+2r+%2B+16+ ALIGN=MIDDLE  ALT=\"+4r+-+8+=+2r+%2B+16+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <---- Started with this equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2r+-+8+=+16+ ALIGN=MIDDLE  ALT=\"+2r+-+8+=+16+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <---- The goal is to \"isolate\" the variable as you know. Subtracting 2r from both sides gets rid of the 2r from the right side.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2r+=+24+ ALIGN=MIDDLE  ALT=\"+2r+=+24+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <----- We added 8 to both sides to get rid of the -8 on the left. (HINT: When we \"move\" terms from one side of the equation to another, we perform an opposite operation. The 8 was a negative, so we add 8 to \"cancel the effect\" BUT WE GOTTA DO IT TO BOTH SIDES. Earlier, we subtracted 2r from both sides (opposite operation of the +2r we began with).)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r+=+12+ ALIGN=MIDDLE  ALT=\"+r+=+12+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <----- Solve for r by dividing both sides by 2.\r<BR>\n" );
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