document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419167>Question 419167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many pounds of fresh water must be added to 30 pounds of sea water containing 16% salt (by weight) in order to reduce the percentage of salt to 12%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293386 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many pounds of fresh water must be added to 30 pounds of sea water containing 16% salt (by weight) in order to reduce the percentage of salt to 12%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "0*x + 0.16*30 = 0.12(x+30)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "0 + 16*30 = 12x + 12*30<BR>\n" );
document.write( "12x = 4*30<BR>\n" );
document.write( "x = (1/3)30<BR>\n" );
document.write( "x = 10 lbs (amt. of fresh water needed)<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );