document.write( "Question 419422: A culture of bacteria obeys the law of uninhibited growth.\r
\n" ); document.write( "\n" ); document.write( "If 500 bacteria are present initially and there are 800 after 1 hour, how many will be present in the culture after 5 hours? \n" ); document.write( "
Algebra.Com's Answer #293384 by ankor@dixie-net.com(22740)\"\" \"About 
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A culture of bacteria obeys the law of uninhibited growth.
\n" ); document.write( "If 500 bacteria are present initially and there are 800 after 1 hour,
\n" ); document.write( " how many will be present in the culture after 5 hours?
\n" ); document.write( ":
\n" ); document.write( "Ao*2^kt = A
\n" ); document.write( "where
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "k = constant value
\n" ); document.write( "t = time in hrs
\n" ); document.write( "A = resulting amt
\n" ); document.write( ":
\n" ); document.write( "500*2^1k = 800
\n" ); document.write( "2^k = \"800%2F500\"
\n" ); document.write( "k*ln(2) = ln(1.6)
\n" ); document.write( "k = \"ln%281.6%29%2Fln%282%29\"
\n" ); document.write( "k = .678
\n" ); document.write( ":
\n" ); document.write( " how many will be present in the culture after 5 hours?
\n" ); document.write( "A = 500*2^(.678*5)
\n" ); document.write( "A = 500*2^(.678*5)
\n" ); document.write( "A = 500*2^3.39
\n" ); document.write( "A = 500*10.4857
\n" ); document.write( "A = 5243 present in the culture after 5 hrs \n" ); document.write( "
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