document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44385>Question 44385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Add or subtract as indicated. Express your result in simplest form.\r<BR>\n" );
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document.write( "4y/y^2 + 6y + 5 + 2y/y^2 - 1\r<BR>\n" );
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document.write( "Thank You!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29337 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, get rid of the fractions by multiplying the entire equation by a common denominator.  In this case the common denominator is \"y^2\"<BR>\n" );
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document.write( "y^2(4y/y^2 + 6y + 5 + 2y/y^2 - 1)<BR>\n" );
document.write( "(y^2)(4y/y^2) + (y^2)(6y) + (y^2)(5) + (y^2)(2y/y^2) - (y^2)(1)<BR>\n" );
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document.write( "Cancel wherever possible; combine like-terms and simplify:<BR>\n" );
document.write( "4y + 6y^3 + 5y^2 + 2y - y^2<BR>\n" );
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document.write( "6y + 6y^3 + 4y^2  <BR>\n" );
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document.write( "Rearrange terms in ascending order by degree:<BR>\n" );
document.write( "6y^3 + 4y^2 + 6y  </SPAN>\n" );
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