document.write( "Question 419440: Suppose you have 80 ft of fence to enclose a rectangular garden.The function A=40x-x^2 gives you the area of the gardne in square feet where x is the width in feet.
\n" ); document.write( "a. What width,x, gives you the maximum garden area?
\n" ); document.write( "b. what is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #293359 by lwsshak3(11628)\"\" \"About 
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Suppose you have 80 ft of fence to enclose a rectangular garden.The function A=40x-x^2 gives you the area of the gardne in square feet where x is the width in feet.
\n" ); document.write( "a. What width,x, gives you the maximum garden area?
\n" ); document.write( "b. what is the maximum area?\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "Standard form for parabola:y=(x-h)^2+k,(h,k) being the (x,y) coordinates of the vertex, from which you can determine the maximum or minimum and the x-coordinate where it occurs.\r
\n" ); document.write( "\n" ); document.write( "A=40x-x^2
\n" ); document.write( "A=-(x^2-40x)
\n" ); document.write( "complete the square
\n" ); document.write( "A=-(x^2-40x+400)+400
\n" ); document.write( "A=-(x-20)^2+400
\n" ); document.write( "ans:
\n" ); document.write( "The width which gives the maximum area=20 ft
\n" ); document.write( "The maximum area = 400 sq ft
\n" ); document.write( "With dimensions 20 ft by 20 ft=80 ft of fencing\r
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