document.write( "Question 419510: ruth is 22 years older than her son. 7 years ago ruth was 3 times her sons age... how old are they now? \n" ); document.write( "
Algebra.Com's Answer #293357 by duckness73(47)\"\" \"About 
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Let r = Ruth's age today
\n" ); document.write( "Let s = Son's age today\r
\n" ); document.write( "\n" ); document.write( "Since Ruth is 22 years older than her son, r = s + 22.
\n" ); document.write( "Seven years ago, when Ruth was r - 7 and her son was s - 7, Ruth was 3 time older than her son which means that r - 7 = 3(s - 7) So we have simultaneous equations:\r
\n" ); document.write( "\n" ); document.write( "r = s + 22
\n" ); document.write( "r - 7 = 3(s - 7)\r
\n" ); document.write( "\n" ); document.write( "Substituting the value of r from the first equation into the second equations, we have:\r
\n" ); document.write( "\n" ); document.write( "(s + 22) - 7 = 3(s - 7)
\n" ); document.write( "s + 15 = 3s - 21
\n" ); document.write( "15 = 2s - 21
\n" ); document.write( "36 = 2s
\n" ); document.write( "18 = s the son's age
\n" ); document.write( "r = s + 22 = 18 + 22 = 40 which is Ruth's age.\r
\n" ); document.write( "\n" ); document.write( "Today, Ruth is 40 and her son is 18.
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