document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419478>Question 419478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this equation: the length of a rectangle is equal to one less than twice the width. if the perimer is equal to 70, what are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293350 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "let width = x \r<BR>\n" );
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document.write( "so, length = 2x -1\r<BR>\n" );
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document.write( "2(x +2x -1) = 70\r<BR>\n" );
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document.write( "=> 3x -1 = 35\r<BR>\n" );
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document.write( "=> x = 12\r<BR>\n" );
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document.write( "length = 23, width = 12 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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