document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419504>Question 419504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this question.  We are learning about percentages and this question is confusing to me.<BR>\n" );
document.write( "I have tried using the order of operations but keep getting stuck.\r<BR>\n" );
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document.write( "   x% =  2x + 1/300     (2x +1 is the entire numerator in the fraction over 300)<BR>\n" );
document.write( "           \r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293346 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "x% =x/100\r<BR>\n" );
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document.write( "x% = (2x +1)/300\r<BR>\n" );
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document.write( "=> x/100 = (2x+1)/300\r<BR>\n" );
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document.write( "=>( x/100 )* 300 = (2x+1)\r<BR>\n" );
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document.write( "=> 3x = 2x+1\r<BR>\n" );
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document.write( "=> 3x - 2x = 1\r<BR>\n" );
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document.write( "so, x = 1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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