document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419440>Question 419440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have 80 ft of fence to enclose a rectangular garden.The function A=40x-x^2 gives you the area of the gardne in square feet where x is the width in feet.<BR>\n" );
document.write( "a. What width,x, gives you the maximum garden area?<BR>\n" );
document.write( "b. what is the maximum area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293329 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the width of rectangular is x ft the length of this rectangle is ( 80-2x)/2<BR>\n" );
document.write( "and the enclosed area is x(80-2x)/2=40x-x^2. A=40x-x^2 is an downward parabola and the value y of its vertex is the maximum area. <BR>\n" );
document.write( " A=-x^2+40x the coordinate x=-b/2a=-40/-2=20 and the A=-20^2+40(20)=400.\r<BR>\n" );
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document.write( "Answer: The maximum enclosed area is 400 sft. </SPAN>\n" );
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