document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44417>Question 44417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me factor  x(2x-y) + y(2x-y)  Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29330 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor out the 2x-y from both terms and get<BR>\n" );
document.write( "x(2x-y) + y(2x-y) =<BR>\n" );
document.write( "(2x-y)(x+y) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );