document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419207>Question 419207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.\r<BR>\n" );
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document.write( "what time will train b catch up to train a?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293263 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.\r<BR>\n" );
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document.write( "what time will train b catch up to train a??<BR>\n" );
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document.write( "Train A is 20 miles ahead at 0450 (40 mph * 0.5 hr)<BR>\n" );
document.write( "Train B gains on train A at 4 mph (44- 40)<BR>\n" );
document.write( "20 mi/4 mph = 5 hours<BR>\n" );
document.write( "0450 + 5 = 0950 or 9:50 AM<BR>\n" );
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