document.write( "Question 419258: find all zeros of the function. f(x)x^3+72-5x^2-18x \n" ); document.write( "

Algebra.Com's Answer #293258 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "finding all zeros of the function. 
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document.write( " f(x)= x^3-5x^2-18x +72
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document.write( "  x^3-5x^2-18x +72 = 0  |If x=3 then zero (27 -45 -54 + 72 = 0)
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document.write( "   (x -3)(x-6)(x+4) =0  |Dividing x^3-5x^2-18x +72  by (x-3)
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document.write( "  (x-3)=0  x = 3
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document.write( "  (x-6)=0  x = 6
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document.write( "  (x+4)=0  x = -4 \n" );
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