document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419283>Question 419283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the product of 5, and 3 more than twice a number, is 85. what is the number?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293257 by </B><A HREF=/tutors/aboutme.mpl?userid=duckness73><B>duckness73(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=duckness73><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=duckness73><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number that we are searching for.\r<BR>\n" );
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document.write( "Note that \"3 more than twice a number\" is 3 + 2x.<BR>\n" );
document.write( "The product of 5 and \"3 more than twice a number\" is 5 (3 + 2x).  We know that this product is 85.  So, we have:\r<BR>\n" );
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document.write( "5 (3 + 2x) = 85<BR>\n" );
document.write( "15 + 10x = 85  (distributive property)<BR>\n" );
document.write( "10x = 70 (subtracting 15 from both sides)<BR>\n" );
document.write( "x = 7 (dividing both sides by 10)\r<BR>\n" );
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document.write( "Answer: 7\r<BR>\n" );
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document.write( "Checking the work:  \"3 more than twice a number\" is 3 + (2 * 7) = 3 + 14 = 17<BR>\n" );
document.write( "The product of 5 and \"3 more than twice a number\" is 5 * 17 = 85.<BR>\n" );
document.write( "Bullseye. </SPAN>\n" );
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