document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419284>Question 419284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 'Lipin thinks of a number.\r<BR>\n" );
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document.write( "She doubles the number and then adds it to the reciprocal of the number.\r<BR>\n" );
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document.write( "She gets the answer 3.\r<BR>\n" );
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document.write( "Write down and solve an equation to work out the two possible numbers that lipin could be thinking of.\r<BR>\n" );
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document.write( "You must show your working.'\r<BR>\n" );
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document.write( "any help would be great :)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293254 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "let number = x\r<BR>\n" );
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document.write( "then 2x + 1/x = 3\r<BR>\n" );
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document.write( "=> 2x^2 + 1 = 3x\r<BR>\n" );
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document.write( "=> 2x^2 -3x +1 = 0\r<BR>\n" );
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document.write( "=>(2x-1)(x-1) =0  , after factorization\r<BR>\n" );
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document.write( "so, x = 1/2 , 1 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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