document.write( "Question 419287: Ann and Bill are both celebrating their birthday today. Two years from now Ann will be twice as old as Bill, while 3 years ago Ann was three times as old as Bill. How old is Bill now? \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #293251 by duckness73(47)\"\" \"About 
You can put this solution on YOUR website!
Let a = Ann's age today
\n" ); document.write( "Let b = Bill's age today\r
\n" ); document.write( "\n" ); document.write( "We know that in two years (when Ann is a + 2 and Bill is b + 2) that Ann will be twice Bill's age, that is:\r
\n" ); document.write( "\n" ); document.write( "a + 2 = 2(b + 2)
\n" ); document.write( "Simplifying this equation, we have:
\n" ); document.write( "a + 2 = 2 b + 4
\n" ); document.write( "a = 2b + 2\r
\n" ); document.write( "\n" ); document.write( "We know that three years ago (when Ann was a - 3 and Bill was b - 3) that Ann was three times Bill's age, that is:\r
\n" ); document.write( "\n" ); document.write( "a - 3 = 3(b - 3)
\n" ); document.write( "Simplifying this equation, we have:
\n" ); document.write( "a - 3 = 3b - 9
\n" ); document.write( "a = 3b - 6\r
\n" ); document.write( "\n" ); document.write( "Putting the two equations together, we have:
\n" ); document.write( "2b + 2 = 3b - 6
\n" ); document.write( "2 = b - 6 (subtracting 2b from both sides)
\n" ); document.write( "8 = b (adding 6 to both sides)\r
\n" ); document.write( "\n" ); document.write( "So today, Bill is 8 and Ann is 18.\r
\n" ); document.write( "\n" ); document.write( "Answer: Bill is 8 today.
\n" ); document.write( "
\n" );