document.write( "Question 419199: 6. In the two squares shown below, the longer square has a side length 1 foot greater than that of the
\n" ); document.write( "smaller square. If the combined area of the two squares is 113 square feet, find the length of the
\n" ); document.write( "side of the smaller square. (Define any variables that you use by using let statements and/or by
\n" ); document.write( "labeling the diagram.)
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Algebra.Com's Answer #293236 by duckness73(47)\"\" \"About 
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Let x = length of the side of the small square. This means that:
\n" ); document.write( "x + 1 = length of the side of the large square.\r
\n" ); document.write( "\n" ); document.write( "The area of the small square is x^2
\n" ); document.write( "The area of the large square is (x + 1) ^ 2\r
\n" ); document.write( "\n" ); document.write( "Since the combined area of the two squares is 113, we have\r
\n" ); document.write( "\n" ); document.write( "x^2 + ((x + 1) ^ 2) = 113
\n" ); document.write( "x^2 + (x^2 + 2x + 1) = 113 (expanding the expression)
\n" ); document.write( "2x^2 + 2x + 1 = 113 (combining like terms)
\n" ); document.write( "2x^2 + 2x - 112 = 0 (subtracting 113 from both sides)
\n" ); document.write( "x^2 + x - 56 = 0 (dividing both sides by 2)
\n" ); document.write( "(x - 7)(x + 8) = 0 (factoring)
\n" ); document.write( "x = 7 or x = -8 (setting each factor to zero and solving)\r
\n" ); document.write( "\n" ); document.write( "So, the side of the small square is either 7 or -8. Since it doesn't make sense for a square to have a side -8 units long, the side of the small square is 7.\r
\n" ); document.write( "\n" ); document.write( "Answer: the length of the side of the small square is 7. (And, BTW, the length of the side of the large square is x + 1 = 7 + 1 = 8).
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