document.write( "Question 419207: trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.\r
\n" );
document.write( "\n" );
document.write( "what time will train b catch up to train a?? \n" );
document.write( "
Algebra.Com's Answer #293235 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The key is to find out how much of a head start train A has. \n" ); document.write( "The difference between 4:20 and 4:50 is \n" ); document.write( "So, A's head start is \n" ); document.write( " \n" ); document.write( "Another key is the fact they will be traveling for the same \n" ); document.write( "amount of time after B passes station \n" ); document.write( "------------- \n" ); document.write( "Start a stopwatch when B leaves station \n" ); document.write( "train A: \n" ); document.write( " \n" ); document.write( "train B: \n" ); document.write( " \n" ); document.write( "---------- \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This says that \n" ); document.write( "4:50 AM + 5 = 9:50 AM answer \n" ); document.write( "---------- \n" ); document.write( "check answer \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is the distance B goes from station \n" ); document.write( "Train A went this distance in \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |