document.write( "Question 419207: trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.\r
\n" ); document.write( "\n" ); document.write( "what time will train b catch up to train a??
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Algebra.Com's Answer #293235 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The key is to find out how much of a head start train A has.
\n" ); document.write( "The difference between 4:20 and 4:50 is \".5\" hrs
\n" ); document.write( "So, A's head start is \"d1+=+40%2A.5\"
\n" ); document.write( "\"d1+=+20\" mi
\n" ); document.write( "Another key is the fact they will be traveling for the same
\n" ); document.write( "amount of time after B passes station
\n" ); document.write( "-------------
\n" ); document.write( "Start a stopwatch when B leaves station
\n" ); document.write( "train A:
\n" ); document.write( "\"+d+-+20+=+40t+\"
\n" ); document.write( "train B:
\n" ); document.write( "\"d+=+44t+\"
\n" ); document.write( "----------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+44t+-+20+=+40t+\"
\n" ); document.write( "\"+4t+=+20+\"
\n" ); document.write( "\"+t+=+5+\"
\n" ); document.write( "This says that \"5\" hrs after B passes station, B catches A
\n" ); document.write( "4:50 AM + 5 = 9:50 AM answer
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\n" ); document.write( "check answer
\n" ); document.write( "\"d+=+44t\"
\n" ); document.write( "\"d+=+44%2A5\"
\n" ); document.write( "\"d+=+220\" mi
\n" ); document.write( "This is the distance B goes from station
\n" ); document.write( "Train A went this distance in \"5+%2B+.5+=+5.5\" hrs
\n" ); document.write( "\"220+=+40%2A5.5\"
\n" ); document.write( "\"220+=+220\"
\n" ); document.write( "OK\r
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