document.write( "Question 418795: I need to see the steps to solving this quadratic equation x^2-2x-13=0 using the method from India and these equations also.\r
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\n" ); document.write( "x^2+12x-64=0
\n" ); document.write( "2x^2-3x-5=0 \n" ); document.write( "
Algebra.Com's Answer #293209 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi
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document.write( "4x^2-4x+3=0
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document.write( "Move the constant term to the right side of the equation
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document.write( "4x^2-4x=-3  
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document.write( "Multiply each term in the equation by four times the coefficient of the x^2 term 
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document.write( "64x^2 -64x = -48 
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document.write( "Square the coefficient of the original x term and add it to both sides of the equation 
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document.write( "64x^2 -64x + 16 = -48 + 16
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document.write( "Take the square root of both sides and complete as shown
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document.write( "(8x -4)^2 =(-32)
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document.write( "(8x -4) = ± sqrt(-32)
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document.write( "      x = (4 ± sqrt(-32))8\r
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "\"x+=+%284+%2B-+sqrt%28+-32%29%29%2F%288%29+\"\r
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