document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44393>Question 44393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=x^5+x^4-2x^3-x^2-x+2 i have to find all real and imaginary zero's, and can you explain the multiplicity of the real zero's for me,thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29319 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=x^5+x^4-2x^3-x^2-x+2 i have to find all real and imaginary zero's, and can you explain the multiplicity of the real zero's for me,thanks\r<BR>\n" );
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document.write( "Since the coefficients add up to zero one of the zeroes is x=1.<BR>\n" );
document.write( "Using synthetic division you can find the remaining factor is <BR>\n" );
document.write( "x^4+2x^3 -x-2.<BR>\n" );
document.write( "The coefficients of this also add up to zero so x=1 is a zero again.<BR>\n" );
document.write( "That is called multiplicity two because x=1 is a zero twice.<BR>\n" );
document.write( "Again using synthetic division you can find the remaining factor is<BR>\n" );
document.write( "x^3+3x^2+3x+2.<BR>\n" );
document.write( "x=-2 is a zero for this. (I got this by graphing it.)<BR>\n" );
document.write( "Synthetic says the quotient is x^2+x+1 which has complex zeroes.\r<BR>\n" );
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document.write( "Hope this helps.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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