document.write( "Question 419177: trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a \n" ); document.write( "

Algebra.Com's Answer #293187 by mananth(16946) $\"\"$ $\"About$

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Train A speed 40 mph
\n" ); document.write( "Train B speed 44 mph
\n" ); document.write( "
\n" ); document.write( "Train A passes station at 04:20
\n" ); document.write( "Train B passes station at 04:50
\n" ); document.write( "
\n" ); document.write( "Difference in time= 00:30 30
\n" ); document.write( "Train A will have covered 20 miles before Train B starts
\n" ); document.write( "
\n" ); document.write( "catch up distance= 20 miles
\n" ); document.write( "catch up speed = 44 -40 mph
\n" ); document.write( "catch up speed = 4 mph
\n" ); document.write( "
\n" ); document.write( "Catchup time = catch up distance/catch up speed
\n" ); document.write( "catch up time= 20 / 4
\n" ); document.write( "catch up time= 5 hours
\n" ); document.write( "catch up time= 300 minutes
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