document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419106>Question 419106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2,8,18,32,50 find the formula for the nth term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293176 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the formula that i came up with is this:\r<BR>\n" );
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document.write( "a[n] = 6 + 6*n + (sum(4*(n-1)) from n = 0 to n = n)\r<BR>\n" );
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document.write( "it works like this:\r<BR>\n" );
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document.write( "a[0] = 6 + 0 + (-4) = 2<BR>\n" );
document.write( "a[1] = 6 + 6 + (-4 + 0) = 8<BR>\n" );
document.write( "a[2] = 6 + 12 + (-4 + 0 + 4) = 18<BR>\n" );
document.write( "a[3] = 6 + 18 + (-4 + 0 + 4 + 8) = 32<BR>\n" );
document.write( "a[4] = 6 + 24 + (-4 + 0 + 4 + 8 + 12) = 50\r<BR>\n" );
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document.write( "it works for all of the numbers listed.\r<BR>\n" );
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document.write( "n has to be greater than or equal to 0\r<BR>\n" );
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document.write( "when n = 0, 4 * (n-1) becomes 4 * (-1) = -4<BR>\n" );
document.write( "when n = 1, 4 * (n-1) becomes 4 * (0) = 0<BR>\n" );
document.write( "when n = 2, 4 * (n-1) becomes 4 * (1) = 4<BR>\n" );
document.write( "when n = 3, 4 * (n-1) becomes 4 * (2) = 8<BR>\n" );
document.write( "when n = 4, 4 * (n-1) becomes 4 * (3) = 12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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