document.write( "Question 419114: A college student earned $8100 during summer vacation working as a waiter in a popular resturant. The student invested part of the money at 8% and the rest at 6&.If the student received a total of $564 in interest at the end of the year, how much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #293138 by mananth(16946)\"\" \"About 
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x+y=8100 ------------------------1
\n" ); document.write( "8.00%x +6.00%y=$564.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8x+6y=$56,400.00 --------2
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\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8x-8y= -64800
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-2y= -$8,400.00
\n" ); document.write( "
\n" ); document.write( "divide by -2
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\n" ); document.write( "y=$4,200.00 investment at 6.00%
\n" ); document.write( "Balance $3,900.00 investment at 8.00%
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