document.write( "Question 419114: A college student earned $8100 during summer vacation working as a waiter in a popular resturant. The student invested part of the money at 8% and the rest at 6&.If the student received a total of $564 in interest at the end of the year, how much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #293138 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x+y=8100 ------------------------1 \n" ); document.write( "8.00%x +6.00%y=$564.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "8x+6y=$56,400.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -8 \n" ); document.write( "we get \n" ); document.write( "-8x-8y= -64800 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "-2y= -$8,400.00 \n" ); document.write( " \n" ); document.write( "divide by -2 \n" ); document.write( " \n" ); document.write( "y=$4,200.00 investment at 6.00% \n" ); document.write( "Balance $3,900.00 investment at 8.00% \n" ); document.write( " \n" ); document.write( " |