document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=419083>Question 419083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working together, Camry, Kyoko, and Priscilla can dig a drainage ditch in 2.5 hours. Working alone, Priscilla can do it in 5 hours, while Camry can do it 3/4 hour faster than Kyoko. Ho long will it take Kyoko to dig the ditch by herself? (Round the answer to 2 decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293135 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let k=number of hrs it takes Kyoko to do the job.<BR>\n" );
document.write( "Priscilla can do 1/5 the job in 1 hr. Kyoko can do 1/k the job in 1 hr and Camry can do 1/(k-.75) the job in 1 hr. Together they can do 1/2.5 of the job in 1 hr.<BR>\n" );
document.write( "1/5 + 1/k + 1/(k-.75)=1/2.5<BR>\n" );
document.write( ".2 + 1/k + 1/(k-.75)=.4<BR>\n" );
document.write( ".2k^2-.15k+k-.75+k=.4k^2-.3k Multiply each side by k^2-.75k<BR>\n" );
document.write( ".2k^2-2.15k+.75=0 <BR>\n" );
document.write( "k=10.39 hrs Quadratic formula.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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