document.write( "Question 419104: please show the working.\r
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document.write( "if 0.25 inches^3 of paint is applied to a circular disk (top only) with a diameter of 20 inches what is the thickness of the paint?\r
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document.write( "At noon car A is traveling north at 30 mph and is located 20 miles north of car B. Car B is traveling west at 50 mph. what is the distance between the cars at 12:45 pm, rounded to the nearest mile? \n" );
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Algebra.Com's Answer #293133 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! if 0.25 inches^3 of paint is applied to a circular disk (top only) with a diameter of 20 inches what is the thickness of the paint? \n" ); document.write( "At noon car A is traveling north at 30 mph and is located 20 miles north of car B. Car B is traveling west at 50 mph. what is the distance between the cars at 12:45 pm, rounded to the nearest mile?\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "First problem: \n" ); document.write( "Volume = Area*height or Area*thickness \n" ); document.write( "thickness=volume/area \n" ); document.write( "Area of a circle= pir^2=3.14*10^2=314 in^2 \n" ); document.write( "thickness=.25 in^3/314 in^2=.000796178 inches \n" ); document.write( "ans: \n" ); document.write( "Thickness of the paint=.000796178 inches\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "second problem: \n" ); document.write( "Distance = speed*time of travel \n" ); document.write( "At 12:45, car A will have traveled 30*(45/60)=90/4=45/2 miles which is added to the 20 miles it has already traveled for a total of 20+45/2 =42.5miles north. \n" ); document.write( "At 12:45, car B will have traveled 50*(45/60)=75/2=37.5 miles west. \n" ); document.write( "We now have a right triangle with legs of 42.5 and 37.5 miles. \n" ); document.write( "Using the pathagorean theorem to solve: \n" ); document.write( "x=sqrt(42.5^2+37.5^)=56.68 miles\r \n" ); document.write( "\n" ); document.write( "ans: \n" ); document.write( "Distance between the cars at 12:45 PM = 57 miles\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |