document.write( "Question 419050: solve the system of equations using gaussian elimination or gauss-jordan elimination.
\n" ); document.write( "1. x-6y=23
\n" ); document.write( " 2x-6y=28\r
\n" ); document.write( "\n" ); document.write( "2. Ellen wishes to mix candy worth $3.44 per pound with candy worth $9.96 per pound to form 24 pounds of a mixture worth $8.33 per pound. How many pounds of the more expensive candy should she use?\r
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Algebra.Com's Answer #293129 by mananth(16946)\"\" \"About 
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1. x-6y=23
\n" ); document.write( " 2x-6y=28
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\n" ); document.write( "\n" ); document.write( "x-6y=23 .............1
\n" ); document.write( "2x-6y=28.............2
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\n" ); document.write( "multiply (1)by 1
\n" ); document.write( "Multiply (2) by -1
\n" ); document.write( "x-6y=23
\n" ); document.write( "-2x+6y= -28
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\n" ); document.write( "Add the two equations
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\n" ); document.write( "-x=-5
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\n" ); document.write( "/-1
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\n" ); document.write( "x=5
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\n" ); document.write( "plug value of x in (1)
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\n" ); document.write( "x-6y=23
\n" ); document.write( "5-6y=23
\n" ); document.write( "-6y=23-5
\n" ); document.write( "-6y=18
\n" ); document.write( "y=-3 \r
\n" ); document.write( "\n" ); document.write( ".....
\n" ); document.write( "2. Ellen wishes to mix candy worth $3.44 per pound with candy worth $9.96 per pound to form 24 pounds of a mixture worth $8.33 per pound. How many pounds of the more expensive candy should she use?\r
\n" ); document.write( "\n" ); document.write( "3.44 ---------------- x
\n" ); document.write( "9.96 ---------------- 24-x
\n" ); document.write( "8.33 ---------------- 24
\n" ); document.write( "....................\r
\n" ); document.write( "\n" ); document.write( "3.44x+9.96(24-x)=8.33*24
\n" ); document.write( "3.44x+239.04-9.96x=199.92
\n" ); document.write( "3.44x-9.96x=199.92-239.04
\n" ); document.write( "-6.52x =-39.12
\n" ); document.write( "/-6.52
\n" ); document.write( "x=6 pounds of $3.44 candy
\n" ); document.write( "18 pounds of $9.96 candy
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