document.write( "Question 419101: How many liters of pure alcohol must be added to 20L of a 40% solution to obtain a 60% solution? \n" ); document.write( "
Algebra.Com's Answer #293123 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "40 ---------------- 20
\n" ); document.write( "100 ---------------- x
\n" ); document.write( "60 ---------------- 20+x\r
\n" ); document.write( "\n" ); document.write( "......
\n" ); document.write( "40*20+100*x=60( 20+x)
\n" ); document.write( "800+100 x=1200+60x
\n" ); document.write( "100x-60x=1200-800
\n" ); document.write( "40x=400
\n" ); document.write( "/ 40
\n" ); document.write( "x=10 liters of 100 % alchohol
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