document.write( "Question 5687: Charles and Paul enter the Center Point - Comfort Hill Country Run. Charles runs at 8 mi/h and Paul at 6 mi/h. If they start together, how long before Charles is 1/4 mi ahead of Paul? \n" ); document.write( "
Algebra.Com's Answer #2931 by prince_abubu(198)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Distance Paul travels = 6*T \n" ); document.write( "Distance Paul is lagging behind = 0.25 miles \n" ); document.write( "Distance Charles travels = 8*T\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are no time delays, so T will be the time they are running together.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since Paul travelled less than Charles, we must add the 0.25 miles (that he was behind by) to his distance equal the distance traveled by Charles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |