document.write( "Question 5687: Charles and Paul enter the Center Point - Comfort Hill Country Run. Charles runs at 8 mi/h and Paul at 6 mi/h. If they start together, how long before Charles is 1/4 mi ahead of Paul? \n" ); document.write( "
Algebra.Com's Answer #2931 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Distance Paul travels = 6*T
\n" ); document.write( "Distance Paul is lagging behind = 0.25 miles
\n" ); document.write( "Distance Charles travels = 8*T\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are no time delays, so T will be the time they are running together.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since Paul travelled less than Charles, we must add the 0.25 miles (that he was behind by) to his distance equal the distance traveled by Charles.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+6T+%2B+0.25+=+8T+\" <---- Setup equation for the situation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+0.25+=+2T+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+T+=+1%2F8\" <--- 1/8 of an hour, or 7 minutes, 30 seconds.
\n" ); document.write( "
\n" );